当前位置:首页 » 《随便一记》 » 正文

50多个Thonny实例代码-Python初学者的福音_huidaoli

27 人参与  2022年04月03日 13:42  分类 : 《随便一记》  评论

点击全文阅读


有不少同学反映我之前发的Python代码太高级看不懂,让写点简单的代码实例集供他们学习。

下面就来分享50多个实例吧,特别适合初学者
实例1:

print('hello world')

实例2:

x = 55 / 11
print(x)

实例3:

x = 50 * 2 + (60 - 20) / 4
print(x)

实例4:

# This is a comment
answer = 42  # the answer

# Now back to the puzzle
text = "# Is this a comment?"
print(text)

实例5:

x = 'silent'
print(x[2] + x[1] + x[0]
      + x[5] + x[3] + x[4])

实例6:

squares = [1, 4, 9, 16, 25]
print(squares[0])

实例7:

word = "galaxy"
print(len(word[1:]))

实例8:

x = 50 // 11
print(x)

实例9:

print(3 * 'un' + 'ium')

实例10:

x = 'py' 'thon'
print(x)

实例11:

print(sum(range(0, 7)))

实例12:

cubes = [1, 8, 27]
cubes.append(4 ** 3)
print(cubes)

实例13:

word = "galaxy"
print(word[4:50])

实例14:

x = 51 % 3
print(x)

实例15:

def if_confusion(x, y):
    if x > y:
        if x - 5 > 0:
            x = y
            return "A" if y == y + y else "B"
        elif x + y > 0:
            while x > y: x -= 1
            while y > x: y -= 1
            if x == y:
                return "E"
    else:
        if x - 2 > y - 4:
            x_old = x
            x = y * y
            y = 2 * x_old
            if (x - 4) ** 2 > (y - 7) ** 2:
                return "C"
            return "D"
        return "H"

print(if_confusion(3, 7))

实例16:

x = 'cool'
print(x[-1] + x[-2]
      + x[-4] + x[-3])

实例17:

words = ['cat', 'mouse']
for word in words:
    print(len(word))

实例18:

def func(x):
    return x + 1

f = func
print(f(2) + func(2))

实例19:

word = "galaxy"
print(word[:-2] + word[-2:])

实例20:

def func(a, *args):
    print(a)
    for arg in args:
        print(arg)

func("A", "B", "C")

实例21:

def ping(i):
    if i > 0:
        return pong(i - 1)
    return "0"

def pong(i):
    if i > 0:
        return ping(i - 1)
    return "1"

print(ping(29))

实例22:

word = "bender"
print(word[1:4])

实例23:

customers = ['Marie', 'Anne', 'Donald']
customers[2:4] = ['Barack', 'Olivia', 'Sophia']
print(customers)

实例24:

def ask(prompt, retries=4, output='Error'):
    for _ in range(retries):
        response = input(prompt).lower()
        if response in ['y', 'yes']:
            return True
        if response in ['n', 'no']:
            return False
        print(output)


print(ask('Want to know the answer?', 5))

实例25:

letters = ['a', 'b', 'c', 'd']
print(len(letters[1:-1]))

实例26:

a = ['a', 'b']
n = [1, 2]
x = [a, n]
print(x[1])

实例27:

letters = ['a', 'b', 'c',
           'd', 'e', 'f', 'g']
letters[1:] = []
print(letters)

实例28:

# Fibonacci series:
a, b = 0, 1
while b < 5:
    print(b)
    a, b = b, a + b

实例29:

for num in range(2, 8):
    if not num % 2:
        continue
    print(num)

实例30:

print(range(5, 10)[-1])
print(range(0, 10, 3)[2])
print(range(-10, -100, -30)[1])

实例31:

def matrix_find(matrix, value):
    if not matrix or not matrix[0]:
        return False

    j = len(matrix) - 1
    for row in matrix:
        while row[j] > value:
            j = j - 1
            if j == -1:
                return False
        if row[j] == value:
            return True
    return False

matrix = [[3, 4, 4, 6],
          [6, 8, 11, 12],
          [6, 8, 11, 15],
          [9, 11, 12, 17]]
print(matrix_find(matrix=matrix, value=11))

实例32:

def maximum_profit(prices):
    '''Maximum profit of a single buying low and selling high'''

    profit = 0
    for i, buy_price in enumerate(prices):
        sell_price = max(prices[i:])
        profit = max(profit, sell_price - buy_price)
    return profit

# Ethereum daily prices in Dec 2017 ($)
eth_prices = [455, 460, 465, 451, 414, 415, 441]
print(maximum_profit(prices=eth_prices))

实例33:

def bubble_sort(lst):
    '''Implementation of bubble sort algorithm'''

    for border in range(len(lst)-1, 0, -1):  
        for i in range(border):
            if lst[i] > lst[i + 1]:
                lst[i], lst[i + 1] = lst[i + 1], lst[i]
    return lst

list_to_sort = [27, 0, 71, 70, 27, 63, 90]
print(bubble_sort(lst=list_to_sort))

实例34:

def concatenation(*args, sep="/"):
    return sep.join(args)

print(concatenation("A", "B", "C", sep=","))

实例35:

x = 5 * 3.8 - 1
print(x)

实例36:

def bsearch(l, value):
    lo, hi = 0, len(l)-1
    while lo <= hi:
        mid = (lo + hi) // 2
        if l[mid] < value:
            lo = mid + 1
        elif value < l[mid]:
            hi = mid - 1
        else:
            return mid
    return -1

    
l = [0, 1, 2, 3, 4, 5, 6]
x = 6
print(bsearch(l,x))

实例37:

words = ['cat', 'mouse', 'dog']
for word in words[:]:
    if len(word) > 3:
        words.insert(0, word)
print(words[0])

实例38:

def make_incrementor(n):
    return lambda x: x + n

f = make_incrementor(42)
print(f(0))
print(f(1))

实例39:

print("""
A
B
C
""" == "\nA\nB\nC\n")

实例40:

print('P"yt\'h"on')

实例41:

def fibo(n):
    """Return list containing
    Fibonacci series up to n.
    """
    
    result = []
    a, b = 0, 1
    while a < n:
        result.append(a)
        a, b = b, a + b
    return result

fib100 = fibo(100)
print(fib100[-1] ==
      fib100[-2] + fib100[-3])

实例42:

def qsort1(L):
    if L:
        return qsort1([x for x in L[1:] if x < L[0]]) + L[:1] \
               + qsort1([x for x in L[1:] if x >= L[0]])
    return []

def qsort2(L):
    if L:
        return L[:1] + qsort2([x for x in L[1:] if x < L[0]]) \
               + qsort2([x for x in L[1:] if x >= L[0]])
    return []

print(qsort1([0, 33, 22]))
print(qsort2([0, 33, 22]))

实例43:

def func(val1=3, val2=4, val3=6):
    return val1 + val2 + val3

values = {"val1":9, "val3":-1}
print(func(**values))

实例44:

print("Answer")
while True:
    pass
print("42")

实例45:

def has_path(graph, v_start, v_end, path_len=0):
    '''Graph has path from v_start to v_end'''

    # Traverse each vertex only once
    if path_len >= len(graph):
        return False

    # Direct path from v_start to v_end?
    if graph[v_start][v_end]:
        return True

    # Indirect path via neighbor v_nbor?
    for v_nbor, edge in enumerate(graph[v_start]):
        if edge: # between v_start and v_nbor
            if has_path(graph, v_nbor, v_end, path_len + 1):
                return True

    return False

# The graph represented as adjancy matrix
G = [[1, 1, 0, 0, 0],
     [0, 1, 0, 0, 0],
     [0, 0, 1, 0, 0],
     [0, 1, 1, 1, 0],
     [1, 0, 0, 1, 1]]
print(has_path(graph=G, v_start=3, v_end=0))

实例46:

pairs = [(1, 'one'),
         (2, 'two'),
         (3, 'three'),
         (4, 'four')]

# lexicographical sorting (ascending)
pairs.sort(key=lambda pair: pair[1])
print(pairs[0][1])

实例47:

# popular instagram accounts
# (millions followers)
inst = {"@instagram":232,
        "@selenagomez":133,
        "@victoriassecret":59,
        "@cristiano":120,
        "@beyonce":111,
        "@nike":76}

# popular twitter accounts
# (millions followers)
twit = {"@cristiano":69,
        "@barackobama":100,
        "@ladygaga":77,
        "@selenagomez":56,
        "@realdonaldtrump":48}


inst_names = set(filter(lambda key: inst[key]>60, inst.keys()))
twit_names = set(filter(lambda key: twit[key]>60, twit.keys()))

superstars = inst_names.intersection(twit_names)
print(list(superstars)[0])

实例48:

words_list = ["bitcoin",
            "cryptocurrency",
            "wallet"]
crawled_text = '''
Research produced by the University of
Cambridge estimates that in 2017,
there are 2.9 to 5.8 million unique
users using a cryptocurrency wallet,
most of them using bitcoin.
'''

split_text = crawled_text.split()
res1 = True in map(lambda word: word in split_text, words_list)
res2 = any(word in words_list for word in split_text)
print(res1 == res2)

实例49:

def encrypt(text):
    encrypted = map(lambda c: chr(ord(c) + 2), text)
    return ''.join(encrypted)


def decrypt(text):
    decrypted = map(lambda c: chr(ord(c) - 2), text)
    return ''.join(decrypted)


s = "xtherussiansarecomingx"
print(decrypt(encrypt(encrypt(s))) == encrypt(s))

实例50:

import random


def guess(a, b):
    return random.randint(a, b)


def check(x, y):
    return y ** 2 == x


x = 100
left, right = 0, x
y = guess(left, right)
while not check(x, y):
    y = guess(left, right)
print(y)

实例51:

print('andunderst'[3:6] + 'andunderst'[6:10] + 'andunderst'[0:3])

上面50个实例代码,大家有兴趣的可以进行下,然后把运行结果发评论区。


点击全文阅读


本文链接:http://m.zhangshiyu.com/post/37238.html

实例  代码  多个  
<< 上一篇 下一篇 >>

  • 评论(0)
  • 赞助本站

◎欢迎参与讨论,请在这里发表您的看法、交流您的观点。

关于我们 | 我要投稿 | 免责申明

Copyright © 2020-2022 ZhangShiYu.com Rights Reserved.豫ICP备2022013469号-1