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PTA 7-2 猜数列游戏2-2_m0_56680402的博客

15 人参与  2021年12月28日 18:14  分类 : 《随便一记》  评论

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在猜数列游戏1的基础上,按顺序循环提供6个不同的数列,每次按顺序给出其中一个数列的连续两个数,再要求用户作答。6个数列大小不固定,即每个数列大小不局限于8个数,可能是10个,100个,1000个数:

  • 1:Fibonacci:1,1,2,3,5,8,13,21
  • 2:Lucas:1,3,4,7,11,18,29,47
  • 3:Pell:1,2,5,12,29,70,169,408
  • 4:Triangular:1,3,6,10,15,21,28,36
  • 5:Square:1,4,9,16,25,36,49,64
  • 6:Pentagonal:1,5,12,22,35,51,70,92

输入格式:

根据提示输入整数数值或Y或N

输出格式:

与猜数列游戏1要求一致。

输入样例:

在这里给出一组输入。例如:

2
Y
4
Y
5
Y
6
Y
9
Y
12
Y
3
Y
7
Y
12
Y
10
Y
16
Y
22
Y
5
Y
11
Y
29
N

输出样例:

在这里给出相应的输出。例如:

The first 2 value is 1,1.What is the next value?
Want to try another sequence?(Y/N)
The first 2 value is 1,3.What is the next value?
Want to try another sequence?(Y/N)
The first 2 value is 1,2.What is the next value?
Want to try another sequence?(Y/N)
The first 2 value is 1,3.What is the next value?
Want to try another sequence?(Y/N)
The first 2 value is 1,4.What is the next value?
Want to try another sequence?(Y/N)
The first 2 value is 1,5.What is the next value?
Want to try another sequence?(Y/N)
The first 2 value is 1,2.What is the next value?
Want to try another sequence?(Y/N)
The first 2 value is 3,4.What is the next value?
Want to try another sequence?(Y/N)
The first 2 value is 2,5.What is the next value?
Want to try another sequence?(Y/N)
The first 2 value is 3,6.What is the next value?
Want to try another sequence?(Y/N)
The first 2 value is 4,9.What is the next value?
Want to try another sequence?(Y/N)
The first 2 value is 5,12.What is the next value?
Want to try another sequence?(Y/N)
The first 2 value is 2,3.What is the next value?
Want to try another sequence?(Y/N)
The first 2 value is 4,7.What is the next value?
Want to try another sequence?(Y/N)
The first 2 value is 5,12.What is the next value?
Want to try another sequence?(Y/N)
num_of_rights:15 num_of_tries:15

代码实现(C++)

#include <iostream>
#include <cstdio>
using namespace std;

int main()
{
	int a1=3,a2=5,i=0,num,sum_t=0,sum_Y=0;
	int h[6][10]={{1,1,2,3,5,8,13,21},{1,3,4,7,11,18,29,47},{1,2,5,12,29,70,169,408},{1,3,6,10,15,21,28,36},{1,4,9,16,25,36,49,64},{1,5,12,22,35,51,70,92}};
	int count=0; 
	int a[6]={0};
	
	char ch,ch2;
	bool go1=true,go2=true;
	while(1)
	{	
		if(i<1)
		{	
			cout << "The first 2 value is " << h[count][a[count]] << ',' << h[count][a[count]+1] << ".What is the next value?" << endl;	
		} 
        i++;    
		if(i<=100&&i>=1)	
			cin >> num;
		while(1)
		{
			if(num!=h[count][a[count]+2]&&i==1)
			{	
                printf("Nice guess but not quite it.\n");
				sum_t++;
			}
			if(num!=h[count][a[count]+2]&&i==2)	
			{
                printf("Wrong a second time.\n");
				sum_t++;
			}
			if(num!=h[count][a[count]+2]&&i==3)
			{
                printf("This is harder than it looks.\n");
				sum_t++;
			}
			if(num!=h[count][a[count]+2]&&i==4)
			{
				sum_t++;
                printf("It must be getting pretty frustrating by now!\n");
                
			}
			if(num!=h[count][a[count]+2])
			{
				printf("Do you want to guess again?\n");	
				cin >> ch2;
				if(ch2=='Y')
				{
					break;
				}
			} 
			if(num == h[count][a[count]+2]||ch2=='N')
			{	
				i=0;
				if(num==h[count][a[count]+2])
				{
					sum_Y++;
					sum_t++;
				}
                printf("Want to try another sequence?(Y/N)\n");
                switch(count)
                {
                	case 0:
						if(a[count]<7) a[count]++;
						else a[count]=0; break;
					case 1:
						if(a[count]<7) a[count]++;
						else a[count]=0; break;
					case 2:
						if(a[count]<7) a[count]++;
						else a[count]=0; break;
					case 3:
						if(a[count]<7) a[count]++;
						else a[count]=0; break;
					case 4:
						if(a[count]<7) a[count]++;
						else a[count]=0; break;
					case 5:
						if(a[count]<7) a[count]++;
						else a[count]=0; break;	
				}
				count++;
				if(count>5)
					count=0;
				cin >> ch;
				if(ch == 'Y')
					break;
				else
				{
					printf("num_of_rights:%d num_of_tries:%d",sum_Y,sum_t);
					exit(0);
				} 
			}
		}
	}
	return 0;
}


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